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Differentiating f ( x ) = 1 0 l n ( x ) + e x x 2 with respect to x , yields: 1

Differentiating f(x)=10ln(x)+exx2 with respect to x, yields:
10ln(x)+exx2+2exx
10+2exx
10x+exx2+2exx
10x+2exx
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