disregard the video in the picture

A ball is thrown upward, from the ground, with an initial velocity of 20 m/s. The approximate value of g is 10 m/s. At what time does the ball reach the high point in its flight? Tossed Ball Velocity up is positive V = +20 w/s a = - 10 w/s down is negative VEV + at += 15 V=+20 m/s+ (-10 w/s?) (1 s) += 25 v=+20 m/s+ (-10 w/s?) (2s) = +20 w/s - 10 m/s = +20 w/s-20 m/s = +low/s =0 + =35 v=+20 w/s+ (-10 m/s?) (35) += 45 V=+20 m/s+ (-10 w/s?) (4 s) =+20 w/s - 30 w/'s =+20 m/s - 40 w/s = =10 w/s =1-20 m/s O 4305 1x The time at which the ball reaches its highest point in flight is S