Do Homework - Homework II ork.aspx?homeworkId=648599151&questionId=15&flushed=false&c... Q 5pm Question 17, 5.3.62 Part 1 of 2 > Thu Jul 20 1:19:01 PM HW Score: 81.25%, 32.5 of 40 points X Points: 0 of 2 Save How many liters of the 30% solution is needed in the mixture? : In mixing a weed-killing chemical, a 30% solution of the chemical is mixed with a 75% solution to get 45 L of a 55% solution. How much of each solution is needed? There needs to be L of the 30% solution in the mixture. (Simplify your answer. Type an integer or a decimal.)