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Do Homework - Module 6: Normal Distribution (Chapter 6 in Book) - Assignment 6 - Google Chrome X mathxl.com/Student/PlayerHomework.aspx?homeworkld=5984663868questionld=8&flushed=false&cld=65251398centerwin=yes INFO240 10FA21 Mustafa Rabboh & |

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Do Homework - Module 6: Normal Distribution (Chapter 6 in Book) - Assignment 6 - Google Chrome X mathxl.com/Student/PlayerHomework.aspx?homeworkld=5984663868questionld=8&flushed=false&cld=65251398centerwin=yes INFO240 10FA21 Mustafa Rabboh & | 11/06/21 8:17 PM Homework: Module 6: Normal Distribution (Chapter 6 in Book) Question 10, 6.2.12-T HW Score: 53%, 5.3 of 10 points Part 4 of 4 x Points: 0 of 1 Save In 2008, the per capita consumption of soft drinks in Country A was reported to be 19.35 gallons. Assume that the per capita consumption of soft drinks in Country A is approximately normally distributed, with a mean of 19.35 gallons and a standard deviation of 5 gallons. Complete parts (a) through (d) below. a. What is the probability that someone in Country A consumed more than 10 gallons of soft drinks in 2008? The probability is .9693. (Round to four decimal places as needed.) b. What is the probability that someone in Country A consumed between 5 and 7 gallons of soft drinks in 2008? The probability is .0047 (Round to four decimal places as needed.) c. What is the probability that someone in Country A consumed less than 7 gallons of soft drinks in 2008? The probability is .0068 (Round to four decimal places as needed.) d. 99% of the people in Country A consumed less than how many gallons of soft drinks? The probability is 99% that someone in Country A consumed less than 29.35) gallons of soft drinks. (Round to two decimal places as needed.) Help me solve this View an example Get more help - Clear all Check

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