do it on Microsoft Excel and explain how , please discuss the question below

The inner and outer surfaces of a 0.5-cm thick 2-m x 2-m window glass in winter are 10C and 3C, respectively. If the thermal conductivity of the glass is 0.78 W/mC: 1- Determine the rate of the heat transfer through the window. 2- Determine the amount of heat loss, in kJ, through the glass over a period of 5 hours. 3- What would your answers be if the glass were 1 cm thick? 4- Reconsider the example Using EES (or other) software, plot the amount of heat loss through the glass as a function of the window glass thickness in the range of 0.1 cm to 1.0 cm. Discuss the results. outer- Solution Given data thicknen of inner and outer surface -0.5cm window's area = A = 2x2 = um temperature Sinner { 10C thermal condue tivity. 0.78 wlmc. 1. The rate of heat traurber through the window. By conduction, we know that KA 47 Q = 0.78 x 4x (10-3) 0.005 21.84 0.005 Q: 4.3kW = 41.3 KW -4368 w - 2. The amount of neat loss through me glass over 0 a period of snown. Q : 4368 x 15x3600) 786240001 . 78.624 MT. Therefore me amount of weret over a period of showr is 19 = 79.624 MJ 3. If me glass were Aniek elem. Q: QL :0.5cm . 2 PLAM: 78.6/2 . 39.3 RIT Pliicm : 39.3 MJ