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Does anyone have the formula to provide a solution for this problem? For a new study conducted by a fitness magazine, 225 females were randomly

Does anyone have the formula to provide a solution for this problem?

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For a new study conducted by a fitness magazine, 225 females were randomly selected. For each, the mean daily calorie consumption was calculated for a SeptemberFebruary period. A second sample of 255 females was chosen independently of the rst. For each of them, the mean daily calorie consumption was calculated for a MarchAugust period. During the SeptemberFebruary period, participants consumed a mean of 2381.2 calories daily with a standard deviation of 210. During the MarchAugust period, participants consumed a mean of 2418.8 calories daily with a standard deviation of 287.5. The population standard deviations of daily calories consumed for females in the two periods can be estimated using the sample standard deviations, as the samples that were used to compute them were quite large. Construct a 95% condence interval for 11.111.2, the difference between the mean daily calorie consumption p1 of females in SeptemberFebruary and the mean daily calorie consumption p2 of females in MarchAugust. Then nd the lower limit and upper limit of the 95% condence interval. Carry your intermediate computations to at least three decimal places. Round your answers to at least two decimal places. {If necessary, consult a list of formulas.) Lower limit: '3 Upper limit

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