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Does the fact that A* is ``optimally efficient'' mean that A* will never expand more nodes than any other algorithm? Why any node in the

Does the fact that A* is ``optimally efficient'' mean that A* will never expand more nodes than any other algorithm?

Why any node in the frontier with f(n) < f^*(n) (the cost of the optimal solution path) will eventually be selected for expansion by A*?

Is it true that all admissible heuristics are equal in the sense that A* will search the states in the same order no matter what the heuristic is?

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