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In 2012, 1,664,479 students took the SAT exam. The distribution of scores in the verbal section of the SAT had a mean / = 494 and a standard deviation o = 114. Let X = a SAT exam verbal section score in 2012. Then X-N( 494, 114) (a) Find the z-score for a = 833.72. (b) This z-score tells us that a = 833.72 cm is standard deviations to the Select an answer of the mean. (c) Suppose that a student's SAT score has a z-score of = = 0.34 . What is the student's actual SAT score. (d) The z-score (= = 0.34) tells you that the male's height is 0.34 standard deviations to the Select an answer of the mean