draw the standard curve this way, you'll use the unknown ratios to go up from the X axis, then you'll hit the standard curve line and go over to the Y and find the log MW. Then you'll find the final MW of the unknowns by raising 10 to the power of that log MW value that you hit on the Y axis.

Example 10^1.3 = 19.95.

can you draw the standard curve for me. Steps on how to do it won't be helpful. I need an illustration, or you can use a digital version i having issues making a standard curve on this information. provide the drawing of the graph please! please put kDa on y axis and ratios on y axis do not put any funky numbers other than what's being provided A is kDa and B is is ratio

Please recall that the last two ratios are considered the unknowns: kDa-9.5 with the ratio of 0.6786, and then kDa-8.7 with the ratio of 0.6214.

(find the final MW of the unknowns by raising 10 to the power of that log MW value that you hit on the Y axis)

draw the standard curve this way, you'll use the unknown ratios to go up from the X axis, then you'll hit the standard curve line and go over to the Y and find the log MW. Then you'll find the final MW of the unknowns by raising 10 to the power of that log MW value that you hit on the Y axis like I showed you yesterday. Example 101.3=19.95. can you draw the standard curve for me. Steps on how to do it wont be helpful. I need an illustration, or you can use a digital version i having issues making a standard curve on this information. provide the drawing of the graph please! AB kDa | Ratio 1800.0214 1200.0786 850.1357 600.25 500.3036 400.4143 25 | 0.6071 200.6786 150.8286 9.50.6786 8.70.6214