dt2d2x+2dtdx+w02x=m1F(t) where we denoted 2mc and w02mk. (a) Assume m=1,c=0,k=4,F(t)=cos(t), and y(0)=0.5,y(0)=0. Find the solution and plot it using any numerical package, e.g., MATLAB, Mathematica, or Python, etc. (b) Determine the solution and plot it for the following parameters; m=1,c=0,k=4, and F(t)=cos(1.75t) with initial value conditions y(0)=0.5 and y(0)=0. (c) Determine the solution and plot it for the following parameters; m=1,c=0.1,k=4, and F(t)=cos(2t) with initial value conditions y(0)=0.5 and y(0)=0. (d) Determine the solution and plot it for the following parameters; m=1,c=4,k=4, and F(t)=cos(2t) with initial value conditions y(0)=0.5 and y(0)=0