During a tennis match, a player serves the ball at $26\mathrm{.}8\frac{m}{s},$ witir the center of the ball leaving the racquet horizontally $2\mathrm{.}52m$ above the court surface. The net is $12\mathrm{.}0m$ away and $0\mathrm{.}900m$ high. When the ball reaches the net, $($a$)$ what is the distance between the center of the ball and the top of the net? $($b$)$ Suppose that, instead, the ball is served as before but now it leaves the racquet at $5\mathrm{.}00$ below the horizontal. When the ball reaches the net, what now is the distance between the center of the ball and the top of the net? Enter a positive number if the ball clears the net. If the ball does not clear the net, your answer should be a negative number. Use $g=9\mathrm{.}81\frac{m}{s^2}.$