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E ) ( * + 5 GCD ( x , y ) : if x = y return x else if x > y return
EGCDx y: if x y return x else if x y return EGCDx y y else return EGCDx y xa Prove that EGCD correctly computes gcdx y$Specifically: i Prove that EGCDx y divides both x and y ii Prove that every divisor of x and y is a divisor of EGCDx yb What is the worstcase running time of EGCDx y as a function of x and yAssume that computing x y requires Olog x log y time.
Unknown. recursion p Kindle Edition.
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