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E) 6.0times 10^(26)C +5.0-mu C point charge is placed at the 0cm mark of a meter stick and a -4.0-mu C charge is placed
E)
6.0\\\\times 10^(26)C
\
+5.0-\\\\mu C
point charge is placed at the
0cm
mark of a meter stick and a
-4.0-\\\\mu C
charge is placed the
50cm
mark. What is the net electric field at the
30cm
mark? . 2/C2)\ A)
5.0\\\\times 10^(5)(N)/(C)
\ B)
9.0\\\\times 10^(5)(N)/(C)
\ C)
4.0\\\\times 10^(5)(N)/(C)
\ D)
1.4\\\\times 10^(6)(N)/(C)
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