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E Homework: Week 15 Chapter 7 Question 11, 7.2.27-T HW Score: 47.69%, 6.2 of 13 points Part 3 of 4 Score: 0 of 1 Save

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E Homework: Week 15 Chapter 7 Question 11, 7.2.27-T HW Score: 47.69%, 6.2 of 13 points Part 3 of 4 Score: 0 of 1 Save Test the claim about the population mean, , at the given level of significance using the given sample statistics. Claim: p = 50; a = 0.03; o = 3.63. Sample statistics: x = 48.3, n = 76 Identify the null and alternative hypotheses. Choose the correct answer below. *A. Ho: H= 50 O B. Ho: H # 50 Ha: H # 50 Ha: H = 50 O C. Ho: H > 50 O D. Ho: H 50 Calculate the standardized test statistic. The standardized test statistic is - 4.08 . (Round to two decimal places as needed.) Determine the critical value(s). Select the correct choice below and fill in the answer box to complete your choice. (Round to two decimal places as needed.) O A. The critical values are + O B. The critical value is Click to select and enter your answer(s) and then click Check Answer. Help Me Solve This View an Example Get More Help - Clear All Check AnswerE Homework: Week 15 Chapter 7 Question 11, 7.2.27-T HW Score: 47.69%, 6.2 of 13 points Part 1 of 4 Score: 0 of 1 Save Test the claim about the population mean, , at the given level of significance using the given sample statistics. Claim: p =50; a = 0.05; o = 3.26. Sample statistics: x = 49.3, n = 62 Identify the null and alternative hypotheses. Choose the correct answer below. O A. Ho: H 50 09 275 [claim] H5: '1 > 275 (claim) : pa 275 (claim) -:I 2- E. H\": u = 275 [claim] . H\": u s 2?5 (claim) :p275 Hi:|_|>2?5 (b) Find the standardized test statistic z, and its corresponding area. 2: (Round to two decimal places as needed.) Enter your answer In the answer box and then click Check Answer. Heb Me Solve This View an Example Get More Help - Clear All Homework: Week 15 Chapter 7 Question 13, 7.2.38-T HW Score: 48.97%, 6.37 of 13 points Part 6 of 6 Score: 0 of 1 Save A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kiloWatt-hours (KWh). You want to test this claim. You find that a random sample of 64 residential customers has a mean monthly consumption of 900 KWh. Assume the population standard deviation is 126 KWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and Ha. Choose the correct answer below. O A. Ho: HS 900 *B. Ho: HS860 Ha: H > 900 (claim) Ha: H > 860 (claim) O C. Ho: H = 900 XD. Ho: H > 900 (claim) Ha: H #900 (claim) Ha: H $ 900 O E. Ho: H > 860 (claim) OF. Ho: H= 860 (claim) Ha: HS 860 Ha: H # 860 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical values are + B. The critical value is 1.64. Identify the rejection region(s). Select the correct choice below. A. The rejection region is z > 1.64. * B. The rejection regions are z 1.64. O C. The rejection region is z 900 (claim) OB. Ho: HS 880 Ha: HS 900 Ha: H> 880 (claim) O C. Ho: H = 880 (claim) O D. Ho: H > 880 (claim) Ha: H # 880 Ha: HS 880 O E. Ho: H = 900 OF. Ho: HS 900 Ha: H # 900 (claim) Ha: [ > 900 (claim) Click to select your answer and then click Check Answer. Help Me Solve This View an Example Get More Help - Clear All Check

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