Question
Each month, an American household generates an average of 28 pounds of newspaper for garbage and/or recycling. Assume this is approximately normally distributed and that
Each month, an American household generates an average of 28 pounds of newspaper for garbage and/or recycling. Assume this is approximately normally distributed and that the standard deviation is 2 pounds. If a household is selected at random, find the probability of it generating between 27-31 pounds per month.
The z score and % to the left of z (also known as the normal distribution probability after you multiply it by 100) are computed in Excel.A value of 1 is used for the cumulative sample size when computing the normal distribution probability since we are considering an individual sheet within the distribution.
Upper End Pounds Newspaper (X) | 31 | Lower End Pounds Newspaper (X) | 27 | |
Mean () | 28 | Mean () | 28 | |
Standard Deviation () | 2 | Standard Deviation () | 2 | |
z-score = (x-)/ | 1.5 | z-score = (x-)/ | -0.5 | |
% to the left of z = NORMDIST*100 | 93.3 | % to the left of z = NORMDIST*100 | 30.9 |
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