Each of two small non-conducting spheres is charged positively, the combined charge being 2 40 /C. If each sphere is repelled from the other by a force having a magnitude of 2.0 N when the two spheres are 50 cm apart, determine the charge on the sphere having the smaller charge. 11 91+ 82=40 - C 5.55 X10 + 1 = 4 x10 F= Rife - 2 11 5 . 5 5 x 10 1 92 = 4 x10 9 2 ri = (9x10' )(8.9-) S. STXIU FO 2 (. 5)2 8192 = 2151 E = 5.S5X/0 C 2 a 2 ( 1 ) 9 X109 - 11 =4x10 $ 3. 712 X 10 8 1 = 5 . ITY10 2 - 6 = 3. 9 5LX 10 C, 1, 4 4 / y/ DC =1.44 15 05:32 00:00