Each step in the following process has a yield of 90.0%. CH, +4C1, CCI, + 4 HCI - CCI, + 2 HF CCI, F, + 2 HCI The CCI, formed in the first step is used as a reactant in the second step. If 3.50 mol CH reacts, what is the total amount of HCI produced? Assume that Cl, and HF are present in excess. 14.0 moles HCI: Incorrect