Earth's oceans have an average depth of $3800m,$ a total area of $3\mathrm{.}63{10}^{8}k{m}^2,$ and an average concentration of dissolved gold of $5\mathrm{.}8{10}^{-9}\frac{g}{L}.$ If a recent price of gold was $\frac{\text{\$}465\mathrm{.}00}{\text{t}\text{r}\text{o}\text{y}oz},$ what is the value of gold in the oceans? $(1$ troy oz $=31\mathrm{.}1g)$ Be sure your answer has the correct number of significant figures.

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