EDUC 5313 Fall 2015, Problem Set 1: Instructions: You may print out this page and write your answers on this sheet. Do not forget to write down your name and the time it took you to complete this assignment at the bottom of this page. 1. For a distribution of scores, X = 40 corresponds to a z-score of z = +1.00, and X = 28 corresponds to a z-score of z = -0.50. What are the values for the mean and standard deviation for the distribution? (Hint: Sketch a distribution and locate each of the z-score positions.) 2. A population of scores with = 73 and = 20 is standardized to create a new population with = 50 and = 10. What is the new value for each of the following scores from the original population? Scores: 63, 65, 77, 83 3. For a normal distribution, a. What z-score separates the highest 10% from the rest of the scores? b. What z-score separates the highest 30% from the rest of the scores? c. What z-score separates the lowest 40% from the rest of the scores? d. What z-score separates the lowest 20% from the rest of the scores? 4. A population consists of the following N = 10 scores: 0, 6, 4, 3, 12, 6, 7, 5, 1, 11 Your task is to enter the data for this variable into SPSS, use the descriptives command to do a z-transformation of the whole distribution into a standardized distribution, and then get the frequencies with mean and standard deviation for both the original raw scores distribution and the standardized distribution. Attach the printout with the frequencies to this homework. Step 1: Open SPSS, go into SPSS Data Editor, enter the ten scores in the first column in the Data View Mode, name this variable \"esteem\" [in the Variable View Mode; click on left bottom buttons to interchange between both], and save the datafile under the name \"esteem-sav\" [via the menu File > Save] Step 2: Do a z-transformation of all the scores for variable \"esteem\" [use either the DESCRIPTIVES command in the syntax window, or do it via menu Analyze > Descriptive Statistics > Descriptives]. Save the standardized variable with a new name, namely \"zesteem\