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electromagnetic ll. please solve all parts except Matlab ASAP please do except MATLAB Problem 4 (13 points) Consider a LHCP wave incident from air onto

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electromagnetic ll. please solve all parts except Matlab ASAP

image text in transcribed

please do except MATLAB

Problem 4 (13 points) Consider a LHCP wave incident from air onto glass at incident angle 30. A LHCP wave can be considered to be composed of 2 perpendicular, linearly polarized waves, i.e. one being the TE polarization and one being the TM polarization. Therefore the incident wave could be written: E = ETE For circularly polarized light, TE = ETM| = 2:0 The magnitude of the incident electric field will therefore be: \JI = VITE 2 + TM 12 = V2a = V2020 = E:0 Or in other words, E20 EO 0,0 = E:0 ETE V2 V2 So the incoming left handed circularly polarized wave can be described by i = ETM1 + ETE 2 = V2 1 ETM = Eng (@s + js) 2 where i and are the unit vectors in the directions of the electric field for the TM and TE components respectively. Calculate, using hand calculations (i.e. show working), for the reflected wave: i) RTM, RTE ii) I, Q, U, V iii) Calculate y and X iv) What is the polarization of the reflected wave? v) Plot the polarization using the posted matlab code. Comment on how your answers compare with the posted matlab code. Hello everyone, I adding a small hint to try and clarify the question of HW4 problem 4, I introduced an error. The text gave the correct directions for the TE and TM components, but I switched them around in the equation. I have highlighted the correction to the question in red: Problem 4 (13 points) Consider a LHCP wave incident from air onto glass at incident angle 30. A LHCP wave can be considered to be composed of 2 perpendicular, linearly polarized waves, i.e. one being the TE polarization and one being the TM polarization. Therefore the incident wave could be written: E = ETE For circularly polarized light, TE = ETM| = 2:0 The magnitude of the incident electric field will therefore be: \JI = VITE 2 + TM 12 = V2a = V2020 = E:0 Or in other words, E20 EO 0,0 = E:0 ETE V2 V2 So the incoming left handed circularly polarized wave can be described by i = ETM1 + ETE 2 = V2 1 ETM = Eng (@s + js) 2 where i and are the unit vectors in the directions of the electric field for the TM and TE components respectively. Calculate, using hand calculations (i.e. show working), for the reflected wave: i) RTM, RTE ii) I, Q, U, V iii) Calculate y and X iv) What is the polarization of the reflected wave? v) Plot the polarization using the posted matlab code. Comment on how your answers compare with the posted matlab code. Hello everyone, I adding a small hint to try and clarify the question of HW4 problem 4, I introduced an error. The text gave the correct directions for the TE and TM components, but I switched them around in the equation. I have highlighted the correction to the question in red

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