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En nuestro laboratorio, completamos valoraciones conductimtricas de FeCl3 + 6H2O y CuCl2+2H2O, lo que provoc que cada uno de ellos sufriera reacciones de doble desplazamiento.

En nuestro laboratorio, completamos valoraciones conductimtricas de FeCl3 + 6H2O y CuCl2+2H2O, lo que provoc que cada uno de ellos sufriera reacciones de doble desplazamiento.

Tengo una pregunta que tiene dos partes:

1- Si pudieras manipular molculas individuales y supieras que tienes 36 molculas de FeCl3, cuntas molculas de NaOH necesitaras para reaccionar completamente con el FeCl3 y cuntas molculas de cada uno de los productos formaras?

2- Y si tuvieras 41 molculas de CuCI2?

gracias! mostrar el trabajo sera de gran ayuda

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