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Encontrar reactivo limitante para la nitracin del benzoato de metilo? cido sulfrico=3ml Masa molar=98.079 cido ntrico-0,8 ml Masa molar=63,01 Benzoato de metilo = 0,47 g

Encontrar reactivo limitante para la nitracin del benzoato de metilo?

cido sulfrico=3ml Masa molar=98.079

cido ntrico-0,8 ml Masa molar=63,01

Benzoato de metilo = 0,47 g o 0,425 ml Masa molar = 136,15 y Masa molar de m-nitrobenzoato = 181,14

Cmo calculo el reactivo limitante?

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