Question
Evaluate the limit, if it exists: lim 240 1+2-1 1+2-1 H (a) If we try pluggin in r=0 into the function, then numerator 1+z-1=
Evaluate the limit, if it exists: lim 240 1+2-1 1+2-1 H (a) If we try pluggin in r=0 into the function, then numerator 1+z-1= T i the result of division is denominator z=> (b) Let's try algebra: multiply both numerator and denominator by (1+z+1) and simplify the numerator only by using the formula (a - b)(a + b)=a-6. (c) In the obtained expression, factor ar appears both in the numerator and the denominator. Simplify further by canceling equal factors of . (d) Find the limit of the simplified form by using Limit Rules. Show your work.
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Calculus Early Transcendentals
Authors: James Stewart
7th edition
538497904, 978-0538497909
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