1. Ex09.02 The manager stated that the average persons who shows up to her store is 45 persons per day. The correct set of hypotheses is?

H0: >= 45 Ha: < 45

H0: = 55 Ha: 55

H0: <= 45 Ha: > 45

H0: = 45 Ha: 45

• 2. Ex09.09 n = 85; 70 favor Student A, = 0.4, alpha = 0.05, Ho: p 0.76 We can conclude = ?

that the population that favors Student A is not significantly greater than 76%

that the population that favors Student A is significantly greater than 76%

that the population that favors Student A is not significantly greater than 70

that the population that favors Student A is not significantly greater than 85

• 3. Ex05.07 p = 0.09; n = 11; x = 5; the binomial probability P(x = 5) = ?

0.0055

0.0051

0.015

0.0015

• 4. Ex08.09 n = 21; sample mean = 15; Sample Standard Deviation = 8; CL = 95%, therefore x1 = ?; x2 = ?

x1=11.36; x2=18.64

x1=18.64; x2=11.36

x1=21.36; x2=28.64

x1=1.36; x2=8.64

5. Ex11.3 n = 32, s = 0.09, The variance of the population is significantly more than 0.008. At 95% confidence, the test statistics is?

31.39

21.39

41.39

11.39

• 6. Ex01.08 Categorical Data

May be only numeric

May be either numeric or non-numeric

May be only non-numeric

May neither be numeric or non-numeric

• 7. Ex08.07 n = 60; mean = 40 Population Standard Deviation = 8; CL = 85.4%, therefore x1 = ?; x2 = ?

x1=48.50; x2=51.50

x1=41.50; x2=38.50

x1=38.50; x2=41.50

x1=28.50; x2=31.50

• 8. Ex05.09 Mean = 7.6, Time = 10, The probability that there are less than 3 occurrences is

0.0182

0.0188

0.0365

0.0245

• 9. Ex09.07 n = 85; average = 2.1, = 0.4, alpha= 0.05, Ho: 2 We can conclude = ?

that the mean of the population is significantly less than 2

that the mean of the population is significantly greater than 85

that the mean of the population is significantly greater than 0.4

that the mean of the population is significantly greater than 2

• 10. Ex06.01 The mean of a standard normal probability distribution is always

2

-1

1

0