Exam Problem 1: I ke piece of metal is heated to 100 "C, and ther, impped unto a beaker containing O.I ke of water at 0 'C and 0.05 kg of ice at 0 "C. Calculate the specific heat of the metal Cry if the specific heat of the water is Cwue - 4186 J/kg "C and the final equilibrium temperature of the mixture. Topublium is 40 "C. (L.= 333,0010 /ke fur water).Given data: Mass of the metal, mpyee = 1 kg Temperature of metal, Tmeta = 100C Mass of water in the beaker, myer = 0.1 kg Temperature of water, Tyaper = 0C Mass of the ice in the beaker, m;. = 0.05 kg Temperature of ice, Tie = 0C Specific heat of water, cwater = 4,186 J/kg"C Latent heat of fusion of ice, L = 333,000 J /kg Final equilibrium temperature of the mixture, T = 40C As no heat lost to surrounding,so heat lost = heat gained Qmetal = Qwater + Qice MmetalCmetal (I'metal - T) = MwaterCwater (T - Twater) + MiceLf MwaterCwater (T - Twater) + miceLf Cmetal = mmetal (Tmetal - T) (0.1 kg) (4,186 J/kg"C)(40"C - 0"C) + (0.05 kg) (333,000 J/kg) Cmetal= (1 kg) (100 C - 40"C) Cmetal = 556.56 J/kg C