Example 2 A flat-shaped belt connecting the two parallel shafts distance between them is 1.2m. Driver pulley diameter 40 cm rotates at a speed of 350 revolution per minute, while follower/driven pulley diameter is 200cm. The coefficient of friction between the belt and pulley surfaces is 0.3 and the maximum allowed tension is 600N. Determine the a.power transmitted by the belt b.the initial tension belt c if the belt is replaced by a V-belt with a 60 determine the transmitted power. Department of Mechanical Precision Engineering MJIIT UTM Kuala Lumpur SolutionQ1 Power is transmitted by belts. Assume that the ideal case means that the mass of the belt is neglected, assume the belt is inelastic and slippage will occur on the small pulley with the small lap angle Given; Diver: 350 =40cm, speed,N, =1500rpm Follower: =200cm x= 1.2 m, F 600N, =0.3 01-002 a=sin -0.5-0.2 x ..=14.5 1.2 = 2.635 180 contact angle,0-180-2a- F F = 600 0.32.635 F =e a. Transmitted power, 2 x 350 P=(Fi-F)=(600-272)0.2 b. Initial tension in the belt = 2.404kW 60 F= F+F 2 600+272 2 =436N c. If the case for v-belt F =e F2 Mesin 600 F 0.3x2.635/sin 30 .. F = 123.5N F =272N Transmitted power P=(T-T)=(600-123.5)0.2 2x350 60 = 7.33kW Ki-Ke