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EXAMPLE 2 Use the Table of Integrals to find x 2 564 x 2 dx . SOLUTIONIf we look at the section of table titled

EXAMPLE 2Use the Table of Integrals to find

x2

564x2

dx.

SOLUTIONIf we look at the section of table titledForms involvinga2-u2, we see that the closest entry is number 34.

u2

a2u2

du=u

2

a2u2

+a2

2

sin1u

a

+C

This is not exactly what we have, but we will be able to use it if we first make the substitutionu=8x.

x2

5-64x2dx=()2

5-2du

8=1

512u2

5-u2du

Then we use Formula 34 witha2=5(soa=

).

x2

5-64x2dx=1

512u2

5-u2du=1

512(-u

2+sin-1()) +C=-x

+sin-1() +C

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