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EXAMPLE 2 Use the Table of Integrals to find x 2 564 x 2 dx . SOLUTIONIf we look at the section of table titled
EXAMPLE 2Use the Table of Integrals to find
x2
564x2
dx.
SOLUTIONIf we look at the section of table titledForms involvinga2-u2, we see that the closest entry is number 34.
u2
a2u2
du=u
2
a2u2
+a2
2
sin1u
a
+C
This is not exactly what we have, but we will be able to use it if we first make the substitutionu=8x.
x2
5-64x2dx=()2
5-2du
8=1
512u2
5-u2du
Then we use Formula 34 witha2=5(soa=
).
x2
5-64x2dx=1
512u2
5-u2du=1
512(-u
2+sin-1()) +C=-x
+sin-1() +C
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