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Example 4.8. The combustion of n-heptane is CH6 + 110, 7CO2 + 8H2O Ten (10) kg of n-heptane is reacted with an excess amount of

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Example 4.8. The combustion of n-heptane is CH6 + 110, 7CO2 + 8H2O Ten (10) kg of n-heptane is reacted with an excess amount of Oz, and 14.4 kg of coz is formed. Calculate the conversion percentage of n-heptane

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