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Example B: 2.54 x 107/1.3 x 102 = 1.95 x107-(-2) = 1.9x10 2. a. 9.65x103 / 2.0 = b. 5.6 x105/1.6 x 105 c.
Example B: 2.54 x 107/1.3 x 102 = 1.95 x107-(-2) = 1.9x10 2. a. 9.65x103 / 2.0 = b. 5.6 x105/1.6 x 105 c. 3.2 x109 / 2.4 x 105 = d. 2.99792 x 108 / 5.520 x 10-7 = e. (A5/A) = PROCEDURE D: Number Log 2 1000 145 0.21 Table 2 PROCEDURE E: For the measurements listed in Table 3, calculate the average width and length Length (cm) Width (cm) 1 61.5 42.3 2 61.4 42.4 3 61.25 42.35 Average Table 3 Using the data from Table 3: 1. a. How many significant digits does the calculated average width have? b. How many significant digits does the calculated average length have? 2. What are the possible sources of error in measuring widths and lengths of a table? 3. Calculate the (Average Width) x the (Average Length). number of significant digits. using the correct A specific Astronomical equation can be solved to find the Absolute Magnitude (M) of a star. m - M = 5 log (d/10) (Again, do the division first before the log) If m = 4.8 and d = 1000, what is M?
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