Question
Exchange current of Fe(CN)6^3- + e = Fe(CN)6^4- reaction at Pt/Fe(CN)6^3-(2.0 mM), Fe(CN)6^4-(2.0 mM), NaCl(1.0M) electrodes (exchange current, i0) was measured at 25C and found
Exchange current of Fe(CN)6^3- + e = Fe(CN)6^4- reaction at Pt/Fe(CN)6^3-(2.0 mM), Fe(CN)6^4-(2.0 mM), NaCl(1.0M) electrodes (exchange current, i0) was measured at 25C and found to be 2.0mA. At this time, the electrode area is 1.0 cm2, and the symmetry factor () is 0.5. Calculate the k0 and Rct values from this.
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Industrial Plastics Theory And Applications
Authors: Erik Lokensgard
6th Edition
1285061233, 978-1285061238
