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Exercise 1 . 6 . Consider this code snippet: } int a , b , * * x , * * y , * *

Exercise 1.6. Consider this code snippet:
}
int a,b,**x,**y,****z;
a=1;
x=&a;
z=&y
**z=x;
b=**y;
}
Line 2 compactly declares two int, a and b; two int *'s,x and y; and one int **,z. Fill in the data corresponding to the final memory configuration:
\table[[int **z,,1016,],[int *,y,,1012],[int *,x,,1008],[int,b,,1004],[int,a,,1000]]
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