Exercise 2 In Lab 2, you wrote Python code that converts 32 miles per Imperial gallon to (approximately) 8.83 litres per 100 km. In this exercise, you'll reimplement this code as a function that will convert any fuel efficiency measured in mpg to the equivalent metric fuel consumption. Step 1: Create a new editor window and save it. Use lab3ex2.py as the file name. Step 2: Type these two assignment statements and the function header. (One Imperial gallon is equal to approximately 4.54609 litres and one mile is equal to approximately 1.60934 km. Recall that the names of constant values in Python are, by convention, usually written in uppercase, with underscores separating the words.) LITRES_PER_GALLON = 4.54609 KMS_PER_MILE = 1.60934 def convert_to_litres_per_100_km(mpg): Complete the function definition; that is, write the function's body. Step 3: Save the code, then click Run. Correct any syntax errors. Step 4: Test your function by typing call expressions in the shell. What value does the function return when the argument is 32? Is this value correct? Does your function return the correct value when the argument is a float (32.0 instead of 32)? Does your function produce correct results when it is called with different positive arguments? How could you verify that these results are correct? Step 5: Close the editor window for lab3ex2.py