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Exercise 6 [4 points] Use substitution to prove that the recursion T(n) = 4T([n/41) + 31([n/3]) + n2 with T(1) = 1 is T(n) =
Exercise 6 [4 points] Use substitution to prove that the recursion T(n) = 4T([n/41) + 31([n/3]) + n2 with T(1) = 1 is T(n) = 12(n)
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