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Exercise 6 [4 points] Use substitution to prove that the recursion T(n) = 4T([n/4]) + 3T([n/3]) + m2 with T(1) = 1 is T(n) =

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Exercise 6 [4 points] Use substitution to prove that the recursion T(n) = 4T([n/4]) + 3T([n/3]) + m2 with T(1) = 1 is T(n) = 12(na)

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