Exercise. Find the indefinite integral of $\frac{1}{3t^2}$ with respect to $t.$

Use the Constant Multiple Rule for antiderivatives.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{1}{3t^2}dt=\frac{1}{3}{\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{1}{t^2}dt$

Write the function under the integral as a power function, because it is more convenient for integration.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{1}{3t^2}dt=\frac{1}{3}{\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{1}{t^2}dt=\frac{1}{3}{\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}{t}^{-2}dt$

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{1}{3t^2}dt=$