Exercise: Power Optimize the operation of a Power Plant to minimize costs. The plant must produce 1000 MWh of electricity in a given period while emitting no more than 2500 g of sulfur (to prevent acid rain). Regular coal or low sulfur coal can be used. Regular coal costs $3/MWh produced by the plant. Low sulfur coal costs 55/MWh. A scrubber can be used to clean stack gasses, but is used with regular coal only. Both regular and low sulfur coal can be burned with the scrubber off, in which case regular coal results in the emission of 12 g/MWh of sulfur and low sulfur coal results in 1 g/MWh. NOTE: none of the amounts or costs used are meant to reflect actual conditions at a power plant. With the additional data given below, use the simplex algorithm solve the problem (e.g., using the Excel Solver Add-in). Given The cost of operating the scrubber is: SC = 0.82 $ MWh The fractional reduction in sulfur emissions with the scrubber on (regular coal only) is: SRF = 0.9 (Unitless) Question(s) 1. What is the cost of producing power using regular coal with the scrubber ON? Answer: CRS = 3 $ MWh +0.82 $ MWh = 3.8 $ MWh 2. How many grams of sulfur are released per MWh of power produced when regular coal is burned with the scrubber ON? Answer: SRS = 12 (1 -0.9) = 1.2 g MWh' 3. How many decision variables are used in the objective function? Answer: Number = 3 (Units not given) 4. How many constraint equation are used in the linear programming model (NOT including non-negativy)? Answer: Number - 2 (Units not given) 5. In the optimal solution, how much energy produced using regular coal with the scrubber OFF? MWh (Answer Length = 8) Score My Answer Practice Investigate 6. In the optimal solution, how much energy is produced using low sulfur coal? 7. In the optimal solution, how much energy is produced using regular coal with the scrubber ON? 8. What is the minimum cost of operating the energy plant? Attempt 1/3 of Part 5/8 for 2.5 points. Points (So Far/Possible/Total): 10/20/20 points. Exercise: Power Optimize the operation of a Power Plant to minimize costs. The plant must produce 1000 MWh of electricity in a given period while emitting no more than 2500 g of sulfur (to prevent acid rain). Regular coal or low sulfur coal can be used. Regular coal costs $3/MWh produced by the plant. Low sulfur coal costs 55/MWh. A scrubber can be used to clean stack gasses, but is used with regular coal only. Both regular and low sulfur coal can be burned with the scrubber off, in which case regular coal results in the emission of 12 g/MWh of sulfur and low sulfur coal results in 1 g/MWh. NOTE: none of the amounts or costs used are meant to reflect actual conditions at a power plant. With the additional data given below, use the simplex algorithm solve the problem (e.g., using the Excel Solver Add-in). Given The cost of operating the scrubber is: SC = 0.82 $ MWh The fractional reduction in sulfur emissions with the scrubber on (regular coal only) is: SRF = 0.9 (Unitless) Question(s) 1. What is the cost of producing power using regular coal with the scrubber ON? Answer: CRS = 3 $ MWh +0.82 $ MWh = 3.8 $ MWh 2. How many grams of sulfur are released per MWh of power produced when regular coal is burned with the scrubber ON? Answer: SRS = 12 (1 -0.9) = 1.2 g MWh' 3. How many decision variables are used in the objective function? Answer: Number = 3 (Units not given) 4. How many constraint equation are used in the linear programming model (NOT including non-negativy)? Answer: Number - 2 (Units not given) 5. In the optimal solution, how much energy produced using regular coal with the scrubber OFF? MWh (Answer Length = 8) Score My Answer Practice Investigate 6. In the optimal solution, how much energy is produced using low sulfur coal? 7. In the optimal solution, how much energy is produced using regular coal with the scrubber ON? 8. What is the minimum cost of operating the energy plant? Attempt 1/3 of Part 5/8 for 2.5 points. Points (So Far/Possible/Total): 10/20/20 points
