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When constructing a confidence interval for the difference between proportions, the two samples must be large enough. This means that

$n_2(1-$hat$(p{)}_2)5$

$n_{1}5$

$]n_1$hat$(p{)}_{1}5$

$n_{2}5$

$n_1(1-$hat$(p{)}_1)5$

$n_2$widehat$(p{)}_{2}5$

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