Exp. 113: Pre-Lab Questions\

Fe^(3+)(aq)+SCN^(-)(aq)FeSCN^(2+)(aq)

\ For the solutions you will prepare in the Procedure Section

A

of Part

I

, calculate the ].\ Table 1 (from Part I)\ \\\\table[[\\\\table[[Beaker],[Number]],\\\\table[[

0.200M

Exp. 113: Pre-Lab Questions Fe3+(aq)+SCN(aq)FeSCN2+(aq) 2. For the solutions you will prepare in the Procedure Section A of Part I2 calculate the [FeSCN2+]. Table 1 (from Part I) Calculations i) Beaker 1 - Sample Calculations shown! #molofSCN=VolumeofSCNsolutionMolarityofSCNsolution=5.0mL1L/1000mL0.0020M=1.00105mol Since SCNis the limiting reagent in the reaction, \# mol of SCN=\# mol of =1.00105mol [FeSCN2+]=LoftotalsolutionmolFeSCN2+=1.00105mol/5.0102L=2.00104M (Total volume of solution is 50 . Find the concentration of FeSCN 2+ in the following beakers (like shown for Beaker 1 )