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Experimental Data - Water & n-Butanol T[K] 0.000 0.000 384.1 0.050 0.253 380.0 0.092 0.388 379.6 0.097 0.402 374.0 0.181 0.556 369.8 0.291 0.660 369.5
Experimental Data - Water & n-Butanol T[K] 0.000 0.000 384.1 0.050 0.253 380.0 0.092 0.388 379.6 0.097 0.402 374.0 0.181 0.556 369.8 0.291 0.660 369.5 0.303 0.666 367.2 0.417 0.724 366.2 0.546 0.750 366.2 0.550 0.753 365.9 0.752 0.754 365.9 0.902 0.754 366.0 0.980 0.760 366.0 0.981 0.763 368.6 0.991 0.839 369.0 0.992 0.850 1.000 1.000 Water / n-Butanol System. A saturated liquid feed of 500 mol/hr containing 40 mole % water is to be fractionated at 101.325kPa (abs) in order to form a distillate containing 70 mole % water and a bottoms product of 10 mole % water. Assuming an ideal solution and a distillate reflux ratio of 3:1. a) Calculate the flowrates (mol/hr) of the distillate and bottoms. b) Determine the theoretical number of trays and the feed tray number for the specified operation. c) Determine the minimum reflux ratio, Rmin and the minimum number of theoretical trays at total reflux. Water & n-Butanol is actually NOT an ideal solution, e.g. Raoult's Law does NOT apply. Using the experimental equilibrium data (at just below atmospheric pressure) is provided on Blackboard. d) Determine the theoretical number of trays and the feed tray number for the specified operation. e) Determine the minimum reflux ratio, RMIN and the minimum number of theoretical trays at total reflux. f) Compare the results of (d) & (e) to the ideal system results (b) & (C). what is the lesson learned? X 1.000 0.923 0.839 Temperature T(F) T(K) 212.2 373.2 215.7 375.2 219.2 377.1 222.8 379.1 226.3 381.1 229.9 383.0 233.4 385.0 236.9 387.0 240.5 388.9 244.0 390.9 TC) 100.1 102.0 104.0 106.0 107.9 109.9 111.9 113.8 115.8 117.8 Vapor Pressure water n-butanol kPa kPa 101.498 51.828 108.8 56.080 116.6 60.613 124.8 65.442 133.5 70.582 142.7 76.047 152.4 81.853 162.6 88.015 173.4 94.549 184.8 101.471 1.000 0.861 0.73 0.607 0.491 0.382 0.279 0.181 0.088 0.000 0.747 0.646 0.537 0.418 0.290 0.151 0.000
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