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Experimental results of the ultimatum game and dictator game can be explained if we assume that every participant is a selfish economic man. we assume

Experimental results of the ultimatum game and dictator game can be explained if

we assume that every participant is a selfish economic man.

we assume that every participant has altruistic motives.

we assume that many participants have interests in other people's payoffs as well as their own payoffs.

Suppose both proposer and responder in the ultimate game are selfish, and their utility functions are =(+1)U=log(x+1) .The proposer is endowed with 1000 cents. The proposer's utility will be ___ if the respondent accept the offer with 500 cents.

log(0)

log(1)

log(500)

log(501)

Suppose both proposer and responder in the ultimate game are selfish, and their utility functions are =(+1)U=log(x+1) .The proposer is endowed with 1000 cents. The respondent's utility will be ___ if the respondent accept the offer with 500 cents.

log(0)

log(1)

log(500)

log(501)

Suppose the proposer and the respondent final payoffs are (1,2)(x1,x2) ,and both of them are altruistic in the ultimate game. The proposer's utility function is =(1+1)+0.5(2+1)U=log(x1+1)+0.5log(x2+1) . The respondent's utility function is =(2+1)+0.2(1+1)U=log(x2+1)+0.2log(x1+1). The proposer is endowed with 1000 cents. The proposer's utility will be ___ if the respondent accept the offer with 200 cents.

log(0)+0.5*log(201)

log(1)+0.5*log(201)

log(800)+0.5*log(200)

log(801)+0.5*log(201)

log(0)+0.2*log(201)

log(1)+0.2*log(201)

log(800)+0.2*log(200)

log(801)+0.2*log(201)

Suppose the proposer and the respondent final payoffs are (1,2)(x1,x2) ,and both of them are altruistic in the ultimate game. The proposer's utility function is =(1+1)+0.5(2+1)U=log(x1+1)+0.5log(x2+1) . The respondent's utility function is =(2+1)+0.2(1+1)U=log(x2+1)+0.2log(x1+1). The proposer is endowed with 1000 cents. The respondent's utility will be ___ if the respondent accept the offer with 200 cents.

log(0)+0.5*log(201)

log(1)+0.5*log(201)

log(200)+0.5*log(800)

log(201)+0.5*log(801)

log(0)+0.2*log(201)

log(1)+0.2*log(201)

log(200)+0.2*log(800)

log(201)+0.2*log(801)

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