explain in detail
TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streaming is gaining in popularity. A poll reported that 56% of 2348 American adults surveyed said they have watched digitally streamed TV programming on some type of device. (a) Calculate and interpret a confidence interval at the 99% confidence level for the proportion of all adult Americans who watched streamed programming up to that point in time. (Round your answers to three decimal places.) (3.:) Interpret the resulting interval. 0 We are 99% confident that the true population proportion lies below this interval. 0 We are 99% confident that the true population proportion lies above this interval. 0 We are 99% confident that this interval contains the true population proportion. 0 We are 99% confident that this interval does not contain the true population proportion. (b) What sample size would be required for the width of a 99% C] to be at most 0.06 irrespective of the value of p? (Round your answer up to the nearest integer.) :l A sample of ultimate tensile strength observations (ksi) was taken. Use the accompanying descriptive statistics output from Minitab to calculate a 99% lower confidence bound for true average ultimate tensile strength, and interpret the result. (Round your answer to two decimal places.) Q3 N Mean Median TrMean StDev SE Mean Minimum Maximum Q1 153 135 . 32 135.33 135 . 34 4 . 58 0. 37 123.20 147 . 70 133.95 139.25 We are 99% confident that the true average ultimate tensile strength is greater than ksi.An article gave the following summary data on shear strength (kip) for a sample of 3/87in. anchor bolts: n : 73, : 4.50, s : 1.50. Calculate a lower confidence bound using a confidence level of 90% for true average shear strength. (Round your answer to two decimal places.) An article reported that for a sample of 58 kitchens with gas cooking appliances monitored during a oneaweek period, the sample mean CO2 level (ppm) was 654.16, and the sample standard deviation was 165.06. (a) Calculate and interpret a 95% (two-sided) confidence interval for true average CO2 level in the population of all homes from which the sample was selected. (Round your answers to two deCimal places.) (3,3)... Interpret the resulting interval. 0 We are 95% confident that this interval does not contain the true population mean. 0 We are 95% confident that the true population mean lies above this interval. 0 We are 95% confident that the true population mean lies below this interval. 0 We are 95% confident that this interval contains the true population mean. (b) Suppose the investigators had made a rough guess of 179 for the value of s before collecting data. What sample size would be necessary to obtain an interval width of 40 ppm for a confidence level of 95%? (Round your answer up to the nearest whole number.)
