Explain to me how to get the answers please or just show work. We're already given the answers I just want to know how to get them.

Note: These skills are required for success within the problems that follow in the Exam Review a). (9x - 4)2 - 15 = 0 b). 6x2 + 7x = 3 x = 4+v15 9 x = 3 c). x2 + 10x = 1 d). 3x2 + 1 = 2x2+ 4x + 1 x = -5#v26 x = 0,4 e). (2x + 1)(x + 3) = 4 f). x3 - 2x2 = x - 2 x = =71v57 x = -1, 1, 2 4 1. Solve. Find ALL solutions, check for extraneous solutions, and identify solutions appropriately. 3x 3 a). V2x +1 - x =-1 b). 1 x2-1 2x+2 x = 4; Note: x = 0 is extraneous x = ; Note: x = -1 is extraneous c). (3x - 4): + 9 = 13 d). (3x - 4): - 14 = 13 x = , 4 x = 13 3 2. Solve Using Substitution. Define the substitution constant. Find ALL solutions, check for extraneous solutions, and identify solutions appropriately. a). 3x* + 14x2 - 5 = 0 b). xi - 2xi - 15 = 0 x = 3 For + x = -27, 125 c. (2x2 + 3x)2 - 2(2x2 + 3x) - 3=0 d). 22x - 4 . 2* = 21 x = - -3-V33 ;-1; -3+v33 x = In (7) In (2) OR x = log2 7 4 Note: x = log2 (-3) is extraneous e). ex -2e* = 3 f). 9* - 6 - 3*+8=0 x = In (3) x = In (4) In(2) In (3) 'In(3) OR x = log: 4, log3 2 Note: x = In(-1) is extraneous3. Solve using properties & rules of logarithms. Find ALL solutions, check for extraneous solutions, and identify solutions appropriately. a). log4 x + log4(x + 2) = log4 3 b). log2 (x - 3) + log2(x + 3 ) = 4 x = 1 x = 5 Note: x = -3 is extraneous Note: x = -5 is extraneous c). log(x) + log(x + 1) = log(3x + 3) d). In(2x - 3) - In(x + 5 ) = 0 x = 3 x = 8 Note: x = -1 is extraneous e). 3 + log(2x + 5) = 2 f). 15 = 5 . 2 4x x = 49 20 x = =In (3) g). 52x+1 = 3x-1 h). 6*-1 = 5 .3* x = In(5)+In (3) x = In (5) +In (6) In(3)-2 In (5) OR x = logs 15 In (6)-In(3) OR x = log2 30 25 4. Solve the Higher Degree Polynomial. List ALL of the Possible Rational Zeros, verify a rational zero using synthetic division, then use the depressed equation to find all zeros of the equation f(x) = 0. a. f(x) = 2x3 - 3x2 - 4x - 1 List PRZ: - 1, -=, =,1; Zeros: -=, 1+ v2 b. f(x) = 3x3- 5x2 - 5x - 1 List PRZ: - 1, - _ _ 3' ,;.1; Zeros: - =, 1+ V2 c. f(x) = x3 + 5x2 + 2x -8 List PRZ: - 8, -4, -2, -1, 1, 2, 4,8; Zeros: -4, -2, 1 d. f(x) = x3 - 7x2 + 16x - 10 List PRZ: - 10, -5, -2, -1, 1, 2, 5, 10; Zeros: 1, 3 1 i 5. Solve the Absolute Value Inequality. Graph the solution on a number line. Express the solution using interval notation. (3-part problem). a. 13* -2-1>5 4 x23 or x 5 - 3 : (-00, - 3 \ U[; , 00). 22 26 35. Solve the Absolute Value Inequality. Graph the solution on a number line. Express the solution using interval notation. (3-part problem). CONT. b. 3x - - 2