Question
Explanation: This is for the CCS C compiler, it is different than standard c, what I have below takes 4 branches of a circuit in
Explanation: This is for the CCS C compiler, it is different than standard c, what I have below takes 4 branches of a circuit in series, stores each branch, and the resistor values in those branches into an array. When that branch is referenced it calls up the total resistance in the designated branch. Below is a picture of the circuit in question.
Question: How would I alter the code below for a parallel circuit involving the 4 branches. Using the basic parallel circuit formula and the array i have already built? would it look something like this (1/(((1/r[1])+(1/r[2])+(1/r[3])+(1/r[4]))?
#include #include #include #include int main() { float r[5]; // i choose to have 5 arrays and skipped 0 to make it easier for user interface // one is able to change the resistor values here in each branch r[1]=(130+70+20);// R= 220 r[2]=(140+60+20);// R= 220 r[3]=(150+50+20);// R= 220 r[4]=(160+40+20);// R= 220 int branch; // %d to place out and %i to request input. printf("Please enter the branch number(1-4): %i",branch); scanf("%d",&branch);//calls back to the array printf(" Total series Resistace of Requested branch is: %f",r[branch]); return 0; }
130R21 1402 Branch 1 Branch 2 Branch 3 Branch 4 160 R11 150 R41 R31 70 60 50 R12 40 R32 R22 R42 R 13 200 R23 20 20 20 R33 R43Step by Step Solution
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