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f: 1 2 2 = 2 1 2 2 0 3 | |=0 1 2 2 => 2 1 0 2 2 3 =0 =>
\f: 1 2 2 = 2 1 2 2 0 3 | |=0 1 2 2 => 2 1 0 2 2 3 =0 => (1 )[(1 )(3 ) 0] + 2[2(3 ) + 4] 2[0 + 2(1 )] = 0 => (1 )[ => 4 + 3] + 2(6 + 2 + 4) 2(2 2 ) = 0 4 +3 +4 3 12 + 4 + 8 4 + 4 = 0 => +5 + 13 = 0 => 5 + 5=0 5 + 5= 0 => ( 5) + 1( 5) = 0 => ( 5)( => + 1) = 0 = 5, , =5 5= ={ |( )= ( ) = 0} { = 5} { } = 15 2 2 => => ( 2 1 1 1 2 0 1 1 1 4 2 2 2 15 0 2 2 4 2 0 2 2 2 35 =0 =0 , =0 1 2 , 1 2 1 2 . ) 1 2 1 => 2 1 0 1 2 0 3 0 2 => 1 0 0 1 3 2 1 2 0 1 0 1 => => 1 1 1 2 1 0 1 1 1 1 1 0 = 0 ,[ =0 , = =1, 2 1 3 1 2 =0 , [ =0 , +2 = 0 => <> + =0 = = 1 =1 1 = 1 1 5= 1 1 1 . : 1 2 2 = 2 1 2 2 0 3 | |=0 1 2 2 => 2 1 0 2 2 3 =0 => (1 )[(1 )(3 ) 0] + 2[2(3 ) + 4] 2[0 + 2(1 )] = 0 => (1 )[ => 4 + 3] + 2(6 + 2 + 4) 2(2 2 ) = 0 4 +3 +4 3 12 + 4 + 8 4 + 4 = 0 => +5 + 13 = 0 => 5 + 5=0 5 + 5= 0 => ( 5) + 1( 5) = 0 => ( 5)( => + 1) = 0 = 5, , =5 5= ={ |( )= ( ) = 0} { = 5} { } = 15 2 2 => => ( 2 1 1 1 2 0 1 1 1 4 2 2 2 15 0 2 2 4 2 0 2 2 2 35 =0 =0 , =0 1 2 , 1 2 1 2 . ) 1 2 1 => 2 1 0 1 2 0 3 0 2 => 1 0 0 1 3 2 1 2 0 1 0 1 => => 1 1 1 2 1 0 1 1 1 1 1 0 = 0 ,[ =0 , = =1, 2 1 3 1 2 =0 , [ =0 , +2 = 0 => <> + =0 = = 1 =1 1 = 1 1 5= 1 1 1
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Introduction to Probability
Authors: Mark Daniel Ward, Ellen Gundlach
1st edition
716771098, 978-1319060893, 1319060897, 978-0716771098
