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* f( x )= m i n s [ 1 , 1 ] i = 1 d s x i * g( x )= i
* f(x)=mins[1,1]i=1dsxi
* g(x)=i=1dminsi[1,1]sixi
* x=(x1,...,xd)^d
Which of f(x)g(x), f(x)=g(x), or f(x)g(x) is true for all x? You need to prove it.
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Algebra And Trigonometry
Authors: Michael Sullivan
10th Edition
0321999290, 9780321999290
