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f(a) (5 points) ||H |F is equal to the square root of the matrix trace of HHT. I H| |F = Vtr( HHT) (b) (5

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\f(a) (5 points) ||H |F is equal to the square root of the matrix trace of HHT. I H| |F = Vtr( HHT) (b) (5 points) Any orthogonal matrix P E Rnxn or Q E Rmxm preserves the Frobenius norm. I HIF = [PH|F = [HQIF (c) (10 points) Prove that |H |F is equal to the root sum square of H's singular values. IHF =

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