\fA random sample of male college baseball players and a random sample of male college soccer players were obtained independently and weighed. The accompanying table shows the unstacked weights (in pounds). The distributions of both data sets suggest that the population distributions are roughly Normal. Using a twotailed test with a signicance level of 0.05, the null hypothesis that the mean weights of soccer and baseball players are equal is rejected. Complete parts (a) through (0) below. Click the icon to view the data table. E) a. If a 95% condence interval for the difference between means was found, would it capture 0'? Explain. The 95% interval would not capture 0, because the hypothesis that the mean weights are the same is rejected by the hypothesis test. The 95% interval would not capture 0, because there appears to be a difference between the mean weights from looking at the data. The 95% interval would capture 0, because the hypothesis that the mean weights are the same is not rejected by the hypothesis test. .0995? The 95% interval would capture 0, because there does not appear to be a difference between the mean weights from looking at the data. b. If a 90% condence interval for the difference between means was found, would it capture 0'? Explain. V because a 90% interval is V a 95% interval and centered at V value, and based on the results of the hypothesis test, a 90% interval Y capture 0. c. Find a 95% condence interval for the difference between means, and explain what it shows. The 95% condence interval for the difference between means (Baseball minus Soccer) is ( , (Round to two decimal places as needed. Use ascending order.) Because the interval |:| capture 0, it shows that the |:| weights for soccer and baseball players |:| signicantly different