\fAn open box is made from a 40-cm by 50-cm piece of tin by cutting a square from each corner and folding up the edges. The area of 40 cm the resulting base is 1344 cm". What is the length of the sides of the squares? 50 cm The length of the sides of the squares is 4 cm. (Simplify your answer.) Next ter 4 hp Julio Serna SERITRAL inator Print Pause Scroll F6 F7 F8 F9 F10 F11 F12 F4 SysRq Lock Break Page Num Backspace Insert Home Up Lock 5 6 U O P Page Delete End Down Hom G HA rancher needs to enclose two adjacent rectangular River corrals, one for cattle and one for sheep. If the river forms one side of the corrals and 390 yd of fencing is available, sheep cattle width find the largest total area that can be enclosed. length The largest total area that can be enclosed is 12675 yds (Simplify your answer.) Next 4.6 apter 4) HOLD -C B E U Q E D 6 F D hp Julio Serna ENTRAL dinator F9 F10 F11 F12 Print F7 F8 Scroll Pause F4 F5 F6 Lock Break Backspace Num nsert Home Page Up Lock CO U P Delete End Page Down HUse the graph of f(x) to find the x-intercepts of the graph and the zeros of the function. The x-intercepts are ( - 2,0), (4.0) (Type ordered pairs. Use a comma to separate answers.) The zeros of the function are x = |- 2,4 (Use a comma to separate answers.) The Vertex of the function is (1,4.5) (Type an ordered pair solution.) Next ter 4) hp Julio Serna CENTRAL pordinator Pause F6 F7 F8 F9 F10 F12 Scrol F11 Lock F4 F5 BYsRo Break Page Num - Backspace Insert Home LOCK P End Page Delete Down G H K EnterK The residents of a downtown neighborhood 7x-6 designed a triangular-shaped park as part of a city beautification program. The park is bound by streets on all sides. The second angle of the triangle is 60 more than the first. The third angle is 6 less than seven times the first. Find the measures of the angles. x+6 The measure of the first angle is x = 20 The measure of the second angle is x + 6 = 260 The measure of the third angle is 7x - 6 = 134 Next 4.4 -40 (Chapter 4) HOLD-CB6096 D Julio Serna CENTRAL wardinator F4 F5 F6 F7 F8 F9 F10 F11 F12 Scroll ause LOCK Break Backspace insert Home Page4+5 1) ( 6- 51 ) 36 - 30 430i+25 61 ( 7 +lei ) ( 7 +(ex) ( 7+bi) 49 + 42 i+ 42 1+ 3lei2( - 1 ) 49 + 84x- -36 13+ 84 i Find slope and y-int : 4 = - 16 Slope : 0 4 - int : ( 0 , - 16) * + X+6+ 7 x-4.= 180 1st angle : 9 x = 180 2 nd angle : 20+ 6 3 " angle : $7 ( 20 ) - 6 X = 20' X+4 = 26 7x-6= 134 : 360 = 1 4 tests = 400 pts 360 - 276 = 84 needed 93+ 89+ 94 = 276 Need 3 60 to get an" A " Score needed for an " A" = Es s2 843 X - int : ( - 2 , 0 ) ( 4 . 0 ) - b = vertex zeros of function : - 2 , 4 20 Vertex of function : ( 1.254.5 ) ? 390- 3 w - b A= 45 A (w) = (390 - 3w) W -3 ( 65)2+ 390 ( 65 ) - 3 W- + 390 w A = 12, 675 yd? ? 390 = 45 maximum area 2 ( - 3 )A ball is thrown directly upward from a height of 4 it with an initial velocity of 24 ft/sec. The function K s(t) = - 16t + 24t + 4 gives the height of the ball, in feet, t seconds after it has been thrown. Determine the time at which the ball reaches its maximum height and find the maximum height. The ball reaches its maximum height of 13 ft 0.75 sec after the ball is thrown. (Simplify your answers. Type integers or decimals. Next 4 -4.6 chapter 4) HOLD-CBELOED OF D 4 hp Julio Serna Print Pause F7 F8 F9 F10 F11 F12 Scroll Break F4 F5 F6 BySRq Page Num Backspace Insert Home Up Lock Page R Delete End Down Home G H K Enter