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fCrivan A, r 34. 11 1 14,0.41 35. 03 1025. 97 $6.09 2509. 60 919:09 37.29 49:99 9429. 56 51. 64 267126 -103. 241 17-63

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\fCrivan A, r 34. 11 1 14,0.41 35. 03 1025. 97 $6.09 2509. 60 919:09 37.29 49:99 9429. 56 51. 64 267126 -103. 241 17-63 92 68 .62 36.20 912 .01 93594 2173.42 1127. 61 34. 55 1 193 . 70 1226- 71 34. 20 1211. 04 37. 73 1423 -55 35-51 10 56. 90 346-15 10970. 035 421 . 31 19 2 21 . 24 h, =ll X 346.15 X, = 421. 31 = 46+21 9 2. = 31.47 S , = 19 8 81. 24 /12123) n 9 9 1 K U= 10470.035 134,6. 15 KS, = 2 209. 096- 2191.38 11 1 1 S, = 997. 276 - 990. oh6 52 2 17. 7 46 8 * = 7. 23 Notice that S= >s, f so we take the test statistic as = 52 = 17.746 5 / 2 7-23 - = 2. 454 rid f = ( n, 1 , n, - 1 ) = (9=1, 11-1)016 = (8, 10 ) Table value off F = 3019 Conclusion: He is accepted at 5.1. level since the calculated value of F / the table value. . : The varupances of the populations are equal2. Take data sets A and B and delete duplicated values such that each value is unique even when pooling the two data sets. Just like with the previous problem, treat data sets A and B as hypothetical data on the weights of children whose parents smoke cigarettes, and those whose parents do not, respectively. Conduct a Wilcoxon Rank-Sum test on the data

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