\fEvaluate the integral: J_, V4-12 dude 4-12 ex-2 +12 O 4T 0 2 1 - O TT [ ] ] 0 2 1 - 2 +0Given the double integral: J2 J 4x x2 (32+12)3/2 dydx, changing the coordinate system, the new limits will be O r: 4 cos 0 to 4 sec 0; 0: 0 to 7/ 4 O r: 4 to 4 sec 0; 0: 0 to 7/ 4 O r: 4 cos 0 to 4 sec 0; 0: 7/4 to T/2 O r: 4 cos 0 to 4; 0: 0 to 7 /2x_2_ 3 y2 = z on the xyplane? (Hint: z = 0) Determine the projection of the surface 0 Ellipse O Hyperbola 0 Two Parallel Lines 0 One Line